## Monday, February 25, 2013

### Errata

This post contains a list of known errors in the book. Equations are rendered using MathJax, which requires Javascript. Please send email to the Gmail account holton.hakim if you know of errors not included below. Thank you --Greg Hakim

• page 14, line 9: "measures" should be "measure"
• page 15, line 3: "...increases the westerly momentum..." is confusing, and should read, "...increases the zonal momentum..."
• section 2.1: all occurrences of "total derivative" should read "material derivative" since the former is used in contexts not related to rates of change following the motion. (Thanks Dale Durran)
• page 57, line 5: (2.54) should be (2.53)
• page 65, problem 2.10: this problem should be in the problem section  for Chapter 3.
• page 91, line 4 should read "... Southern Hemisphere ($$f<0$$) case."
• page 112, line 8: $$\frac{U \theta^*}{\rho H L} + \frac{f \theta^*}{H}$$ should read $$\frac{U \theta^*}{\rho^* H L} + \frac{f \theta^*}{\rho^* H}$$
• page 115, equation (4.31) is missing a minus sign.
• page 115, sentence above equation (4.32) should read, "Integrating the hydrostatic equation from the top of the fluid, $$h(x,y,t)$$, to level $$z$$, gives..."
• page 116, equation (4.35) and the logic leading to it, is wrong. Since pressure depends on (x,y,z,t), the total differential has contributions from those variables that give an identity for Dp/Dt. Instead, one may take $$\frac{D}{Dt}$$ of (4.32), giving $$\frac{Dp}{Dt} = \rho_0 g\left(\frac{Dh}{Dt} - w \right)$$ which yields (4.36) at $$z = h$$.
• page 117, Figure 4.11: although technically correct, the labels for $$\theta$$ on the right side of the figure should reflect $$z$$.
• page 118, the third line of section 4.5.1 should read "...density depends only on pressure." (thanks Leo Kroon).
• page 118, Figure 4.12: in the upper panel of the figure, the rightmost vorticity value of $$\zeta < 0$$ should read $$\zeta = 0$$. (Thanks Uma Bhatt)
• page 142, last line: $$v' = -ikg/f$$ should read $$v' = ikgh'/f$$  (thanks Fang-Ching Chien)
• page 143, 4th line: $$u' = c/\bar{h}$$ should read $$u' = ch'/\bar{h}$$ (thanks Fang-Ching Chien)
• page 150, line before equation (5.73): should read "Using (5.71) and (5.72) to evaluate (5.70)..." (thanks Ewan Short)
• page 151, three lines below equation (5.70): "...form of (5.49):" should read "...form of (5.69):" (thanks Leo Kroon)
• page 152, Figure 5.11: $$\hat{M}_0$$ should read $$M_0$$  (thanks Fang-Ching Chien)
• page 162, below equation (5.111) should read " which reduces to (5.107) when the..." (thanks Tom Guinn)
• page 162, 6 lines from the bottom should read " ...(see Problem 5.15) ..." (thanks Tom Guinn)
• page 181, line -8: "...we can make..." (extra "we") (Thanks Fang-Ching Chien)
• page 190, line -10: "...and if the zonal wind increases..." should be "...and a zonal wind that increases..."
• page 195, equation (6.37): a factor of $$f$$ is missing from the right side.  The full equation should read:$${\rm L} \frac{\partial p}{\partial t} \, = \, -{\bf V}_g {\bf \cdot} {\bf \nabla}_h (f \zeta_g) - {\bf V}_g {\bf \cdot \nabla}_h \left(f^2 \frac{\partial}{\partial z}\frac{d\bar{\theta}}{dz}^{-1} \theta \right)$$ (Thanks Joel Norris)
• page 197, equation (6.40): $$\zeta$$ should be $$\zeta_g$$ (thanks Fang-Ching Chien
• page 198, equation (6.42): $$\zeta$$ should be $$\zeta_g$$ (thanks Fang-Ching Chien
• page 199, equation (6.47): the very last term should read $$-v_j \frac{\partial}{\partial x_j}\frac{\partial\zeta}{\partial x_3}$$ (Thanks Joel Norris)
• page 199, equation (6.49): the right hand side of the equation should have a minus sign.
• page 201, line below equation (6.55): $$\partial v_i \partial x_3$$ should read $$\partial v_i/ \partial x_3$$. The three lines after (6.55) are mixed together, and should read "... is the deformation term. The deformation term is one of two terms in the divergence of the Q-vector. Noting that ..., in vector notation, " (thanks Fang-Ching Chien)
• page 203, Fig. 6.17: the abscissa label should be $$y$$ (thanks Fang-Ching Chien)
• page 205, last sentence: "...we expect clouds to form, releasing latent heat." (thanks Fang-Ching Chien)
• page 206, line 4, (see Figure 6.10a) should read: (see Figure 4.10a) (thanks Fang-Ching Chien)
• page 240. The first sentence of constraint 1. should read, " If $$\partial\bar{u}/\partial z^* = 0$$ at $$z^* = 0$$ ..." (Thanks Nora Leps)
• page 262: There is an extraneous $$h$$ in the definition of wind speed below the main equations. (Thanks Tom Guinn)
• page 268: Footnote 3 should read "...eddy stress (see footnote 2)..." (Thanks Ben Green)
• page 314, equation (9.58) should read: $$m \, = \, r v + \frac{1}{2} f r^2$$
• page 373, line 10: ..."water vapor increase..." should be "...water vapor increases..."
• page 401: equations (11.27) and (11.28) should read $$-\partial\Phi^{'}/\partial x$$ and $$-\partial\Phi^{'}/\partial y$$, respectively. (Thanks Rob Korty)
• page 499: in the statement of the divergence theorem $${\bf V \cdot B}$$ should read   $${\bf \nabla \cdot B}$$ (Thanks Fred Carr)
• page 499: in the statement of Stokes' theorem $${\bf V \times B}$$ should read $${\bf \nabla \times B}$$ (Thanks Fred Carr)

1. Great article, I am very happy to visit this site. I more hope you will publish new topics for us.

2. Great book. I am studying it and have a query.
On page 77, How VR+fR²/ 2 expression for the absolute angular momentum about the axis of rotation for the circularly symmetric motions can be deduced?
Which is the axis of rotation (Earth's axis of rotation)? And, does R refer to high's or low's radius of curvaure or the distance to the Earth's axis of rotation?

3. Eugenio,

In general, the magnitude of the angular momentum is RV, where R is the distance from the axis of rotation and V is the magnitude of the linear momentum vector. For the cases considered in section 3.2.5, R represents the distance from the center of the cyclone or anticyclone. There are two contributions to the angular momentum: (1) the wind field, RV, and (2) the Earth's rotation. For (2), the contribution to linear momentum is \omega\sin\phi R, where \omega is the planetary rotation rate and \phi is the latitude. In terms of the Coriolis parameter, f = 2\omega\sin\phi, that means (2) contributes fR^2/2 to the angular momentum.

-Greg Hakim

1. Thank you for your clarification.

4. Hi Greg, could you explain me something regarding the exercise 7.1 from the 5th edition? I saw the solution from the instructor's manual and there it says that the e1 amplification time is just 1/alfa, but I was expecting that it woulb be e*(1/alfa). If I'm wrong, could explain it to me, please? Thank you.

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6. In the fourth line of the last paragraph on page 41, should it be 1.33 and 1.34 equations instead of 1.31 equation?